A beam of light consisting of wavelengths 650 nm and 550 nm illuminates the Young's double slits with separation of 2 mm such that the interference fringes are formed on a screen, placed at a distance of 1.2 m from the slits. The least distance of a point from the central maximum, where the bright fringes due to both the wavelengths coincide, is 
.
Text Solution
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(429) Given wavelengths are 
and 
.
Slit separation 
.
Distance to screen 
.
For the bright fringes of both wavelengths to coincide at a distance 
from the central maximum, we have:
where 
and 
are integers representing the order of the fringes.
This simplifies to 
.
The least values for coincidence are 
and 
.
The least distance 
is given by:
.
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